35x^2-216x+112=0

Solution for 35x^2-216x+112=0 equation:

35x^2-216x+112=0

a = 35; b = -216; c = +112;
Δ = b2-4ac
Δ = -2162-4·35·112
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30976}=176$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-216)-176}{2*35}=\frac{40}{70}
=4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-216)+176}{2*35}=\frac{392}{70}
=5+3/5
$